Question

plz do it in notebook.

Answer 1

Heya !
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 I only know 1st one 

$\frac{-3a^2b^2}{4} / \frac{3ab^3}{2}$

$\frac{3a^2b^2}{4} X \frac{2}{3ab^3}$

$\frac{3 X a Xa X b X b }{3 X a X a X b X b X b}$

$\frac{-b}{a}$