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Here is the solution :
Given that,
10^2y = 25,
=> We know that, (a^m)^n = (a^mn)
=> 10^2y = (10^y)^2,
=> Applying root on both sides
=> 10^ y = +5 or - 5,
We need to find,
10^-y, = 1/10^y
=> 10^-y = Either 1/5 or -1/5
So both (a) and (d) are correct,
But in general we won't use √25 = -5,
So most people think only (d) is right ! But remember that, (a) is also correct !
Therefore : 10^-y = +1/5 or -1/5,
Hope you understand, Have a Great day !
Thanking you, Bunti 360 !!
Given that,
10^2y = 25,
=> We know that, (a^m)^n = (a^mn)
=> 10^2y = (10^y)^2,
=> Applying root on both sides
=> 10^ y = +5 or - 5,
We need to find,
10^-y, = 1/10^y
=> 10^-y = Either 1/5 or -1/5
So both (a) and (d) are correct,
But in general we won't use √25 = -5,
So most people think only (d) is right ! But remember that, (a) is also correct !
Therefore : 10^-y = +1/5 or -1/5,
Hope you understand, Have a Great day !
Thanking you, Bunti 360 !!
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