Math, asked by hamzagaming786204, 6 hours ago

plz do it. this is a maths problem​

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Answered by misscutie94
0

Answer:

Solution :-

\dfrac{y - (4 - 3y)}{2y - (3 + 4y)} = \dfrac{1}{5}

\implies\dfrac{y - 4 + 3y}{2y - 3 - 4y} = \dfrac{1}{5}

\implies\dfrac{y + 3y - 4}{2y - 4y - 3} = \dfrac{1}{5}

\implies\dfrac{4y - 4}{- 2y - 3} = \dfrac{1}{5}

\implies 20y - 20 = - 2y - 3

\implies 20y + 2y = - 3 + 20

\implies 22y = 17

\implies y = \dfrac{17}{22}

\therefore\sf\: The\: answer\: of\: this\: question\: is\: \dfrac{17}{22}

Answered by Aʙʜɪɪ69
0

Step-by-step explanation:

Hope this answer helps you !!!!!

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