Question

plz do this i will mark as brainleist.....with explanation !!! ​

Answer 1

Answer:

a³+b³+c³-3abc=1174

Step-by-step explanation:

given that:

a+b+c=15

a²+b²+c²=83

a³+b³+c³-3abc=?

solution:

we know that:

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²)-(ab+b-c+ac) ---(A)

we also know that

(a+b+c)²=a²+b²+c²+2(ab+bc+ac)---(B)

putting the values in eq B

(15)²=83+2(ab+b-c+ac)

225-83=2(ab+ bc+ac)

142/2=(ab+bc+ac)

ab+bc+ac=71

now using these values in eqn (A)

a³+b³+c³-3abc=(15)(83)-(71)

a³+b³+c³-3abc=1245-71

a³+b³+c³-3abc=1174