Simplify..
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Step-by-step explanation:
let x= 1/√3 +√2
y= 2/√5 -√3
z= 3/√2-√5
x-y-z=? --A
rationalize x= 1*√3 -√2/√3+√2 *√3 - √2
x=√3-√2/+3-2=√3-√2
rationalize y= 2*√5 + √3 /√5 - √3*√5+√3
Y=2(√5+√3)/5-3=√5+√3
rationalize z= 3*√2+√5/√2-√5*√2+√5
z=3(√2+√5)/2-5
z=3(√2+√5)/-3
z=-(√2+√5
using the values of x y and z in eqn A
=√3 -√2 -√5. -√3 +√2 +√5
=0
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