plz do work and my answer give me
Attachments:
Answers
Answered by
1
In Δ BDE & Δ CDF,
<BED = <CFD (each equals to 90°)
BD = CD (D is the mid point of BC)
ED = FD (Given)
Therefore, ΔBDE congruent to ΔCDF
(RHS rule) .
<B = <C (CPCT)
<BED = <CFD (each equals to 90°)
BD = CD (D is the mid point of BC)
ED = FD (Given)
Therefore, ΔBDE congruent to ΔCDF
(RHS rule) .
<B = <C (CPCT)
Answered by
1
Answer
Given ,D IS MID POINT
SO BD =CD
TO PROVE ANGLE B = ANGLE C
IN TRIANGLE BDE AND CDF
ANGLE E = ANGLE F ( EACH 90 )
BD = CD ( AS D IS MID POINT )
DE = DF ( GIVEN )
SO TRIANGLE BDE IS CONGRENT TO TRIANGLE CDF (BY RHS)
SO ANGLE B = ANGLE C ( BY CPCT)
PROVED
Given ,D IS MID POINT
SO BD =CD
TO PROVE ANGLE B = ANGLE C
IN TRIANGLE BDE AND CDF
ANGLE E = ANGLE F ( EACH 90 )
BD = CD ( AS D IS MID POINT )
DE = DF ( GIVEN )
SO TRIANGLE BDE IS CONGRENT TO TRIANGLE CDF (BY RHS)
SO ANGLE B = ANGLE C ( BY CPCT)
PROVED
Similar questions