Question

plz explain it with clear cut answer..No direct answer plzzzzzzzz..

NEET 2012​

Answer 1

Answer

Aluminium reacts with caustic soda in accordance with the reaction

The reaction of aluminium with caustic soda can be represented as:

Therefore volume of hydrogen at STP released when 0.15g of Al reactsv

=0.15 x 3 x 22.4 /54 = 187ml

Now P1 = 1 bar,

P2 = 1 bar

T1 = 273 K

T2 = 20 + 273 = 293 K

V1 = 187 ml

V2 = x

When pressure is held constant,then

V2 = P1 V1 T2 / P2 T1

OR

x = 1 X 187 X 293 / 0.987 X 273

= 201 ml

Therefore, 201 mL of dihydrogen will be released.

Answer 2

Answer:

hey

Explanation:

Answer seems to be

Option D