plz factorise 8x^3-(2x-y)
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8x^3-(2x-y)^3 = (2x)^3-(2x-y)^3 Apply formula a^3-b^3= (a-b)(a^2-ab+b^2) Put a= 2x,b= 2x-y = (2x-2x+y){(2x)^2-2x*(2x-y)+(2x-y)^2} = y{(4x^2-4x^2+2xy+4x^2-4xy+y^2)} = y (4x^2-2xy+y^2)
ved3331:
it's OK
it was my holiday homework it was hard for me to do so thanks again very much✌✌
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