Math, asked by abhinav101, 1 year ago

plz factorise these equations

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Answered by Aaryadeep
3
@
216-8x³-27y³-108xy
=>(6)³+(-2x)³+(-3y)³-3(6)(-2x)(-3y)
=>{6+(-2x)+(-3y)}{6²+(-2x)²+(-3y)²-(6)(-2x)-(-2x)(-3y)-(-3y)(6)
=>(6-2x-3y)(36+4x²+9y²+12x-6xy+18y)
@:-)

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Answered by prerna16
3
(6)^3 +(2x)^3 +(-3y)^3 - 3(6)(-2x)(-3y)
using identity x^3+y^3+z^3-3xyz
= {6+(-2x)+(-3y)}{ (6)^2+(-2x)^2+(-3y)^3 -(6)(-2x)-(-2x)(-3y)-(-3y)(6)
= (6-2x-3y)(36+4x^2+9y^2+12x-6xy+18y)

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