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AB||CD, so x=60°.......alternate interior angles
Y=40°.......alternate interior angles
60°+Z+40°=180°.......linear pair
100°+z=180°
z=180°-100°=80°
angle b+angle c=180°......consecutive interior angles
75°+angle c =180°
C=180°-75°=105°
y+angle c =180°.......linear pair
y+105°=180°
y=180°-105°=75°
x=75°
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4
Answer:
AB||CD, so x=60°.......alternate interior angles
Y=40°.......alternate interior angles
60°+Z+40°=180°.......linear pair
100°+z=180°
z=180°-100°=80°
angle b+angle c=180°......consecutive interior angles
75°+angle c =180°
C=180°-75°=105°
y+angle c =180°.......linear pair
y+105°=180°
y=180°-105°=75°
x=75°
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