Math, asked by sandeep187350, 1 year ago

plz fast solve with explain

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Answered by SillySam
1
Heya mate, Here is ur answer


Cot 12° × cot 38° × cot 52° × cot 60° × cot 78°


<b><u>Rearranging the terms </u></b>


Cot 12° × cot 78° × cot 38°× cot 52° × cot 60°


= cot 12° × cot (90-12°) × cot 38°× cot(90-38°)× cot 60°


= cot 12° × Tan 12° × cot 38°× Tan 38° × cot 60°


 =  \cot(12) \times  \frac{1}{ \cot(12) }  \times  \cot(38) \times  \frac{1}{ \cot(38) }  \times  \cot(60)


= Cot 60°


 =  \frac{1}{ \sqrt{3} }

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Answered by Panzer786
0
Cot12° × Cot38° × Cot 52° × Cot 60° × Cot78°




Cot12° × Cot78° × Cot38° × Cot52° × Cot 60°




Cot 12° × Cot ( 90 - 12° ) × Cot38° × Cot(90-38° ) × Cot60° .



Cot12° × Tan12° × Cot38° × Tan38° × Cot60°



1/ Tan12° × Tan12° × 1/ Tan38° × Tan38° × Cot60°


1 × 1/√3



1/✓3.
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