Question

plz fastly answer me ( answer is 16πcm cubic) plz solve it don't be oversmart ​

Answer 1

Answer:

PPZ MARK IT AS BRAINLIEST AND ALSO LIKE IT

Step-by-step explanation:

L.L = H.H + R.R

25= H.H + 16

perpendicular height = 3

Volume of cone = 1/3πr.rh

=1/3π*16*3

= 16π cubic cm

Answer 2

Question :

If right Circular Cone has radius 4.cm slant height 5 cm and then What is its volume.

Given :

• Radius ( r ) = 4 cm.
• Slant height ( l ) = 5 cm.

To Find :

Volume of Right Circular Cone.

Solution :

We have, Right Circular Cone.

$\rule{90}3$

We need to Find Height.

★ Apply Pythagorean theorem.

$\tt : \implies {H}^2 = {P}^2 + {B}^2$

$\tt : \implies {Slant \:height}^2 = {P}^2 + {Radius}^2$

$\tt : \implies {5}^2 = {P}^2 + {4}^2$

$\tt : \implies 25 = {P}^2 +16$

$\tt : \implies 9 = {P}^2$

$\tt : \implies 3 = P$

Now, We have, Height ( Perpendicular to right Circular Cone )

$\tt \dagger \: \: \: \: \: Volume \: of \: Right \: Cone = \frac{1}{3} \times \pi {r}^{2} h$

A/Q,

$\tt : \implies V_{Cone} = \frac{1}{3} \pi {r}^{2} h$

$\tt : \implies V_{Cone} = \dfrac{1}{3} \pi { \big(4 \big)}^{2} \times 3$

$\tt : \implies V_{Cone} = \dfrac{1}{3} \times \pi \times 16 \times 3$

$\tt : \implies V_{Cone} = 16\pi.$