Question

plz find the 31st question's answer​

Answer 1

Answer:

Step-by-step explanation: Draw a perpendicular to BC from A called AP that intersects DE at q

DE║BC

So, by BPT, DE/BC = AQ/AP = 5/8

DE/BC × AQ/AP = 5/8 × 5/8 = 25/64

DE × AQ/ BC × AP = 25/64

Multiplying numerator and denominator by 1/2,

1/2 × DE × AQ/1/2 × BC × AP = ar(ΔADE)/ar(ΔABC) =25/64

since 1/2 × base × height = Area of triangle

Since ar(ΔADE) = 10cm²

ar(ΔADE)/ar(ΔABC) = 10/ar(ΔABC) = 25/64

ar(ΔABC) = 64/25 × 10 = 25.6cm²

Answer 2

hope it helps:-).................................