Question

plz find the answer​

Answer 1

<PAB=<ABC -----(alternate interior angles)

Thus <ABC=50°

We know that an exterior angle of a triangle is equal to the sum of the 2 interior opposite angles.

Hence----

<ACS=<ABC+<BAC

127°=50°+<BAC

<BAC=127°-50°

= 77°

Answer 2

Answer:

<BAC=77°

Step-by-step explanation:

{since <ACS+<QAC=180° (Alternate interior angle)}

so <QAC=180°-127°=53°

and <PAC+<BAC+<QAC=180°

50°+<BAC+53°=180°

<BAC=180°-50°-53°

<BAC=180°-103°

<BAC=77°