Question

plz find the value of x and give the verification ​

Answer 1

Answer:

Value of x is 6/5

☸Given☸

➺$\sf{\dfrac{3(2+x)-5(2x-3)}{5-3x}=9}$

➳To Find:

• Value of x

✯Solution✯

$\longrightarrow\sf{\dfrac{3(2+x)-5(2x-3)}{5-3x}=9}$

$\longrightarrow\sf{3(2+x)-5(2x-3)=9(5-3x)}$

$\longrightarrow\sf{6+3x-10x+15=45-27x}$

$\longrightarrow\sf{27x+3x-10x=45-6-15}$

$\longrightarrow\sf{x(27+3-10)=45-21}$

$\longrightarrow\sf{x(20)=24}$

$\longrightarrow\sf{20x=24}$

$\longrightarrow\sf{x=\dfrac{24}{20}}$

$\longrightarrow\sf{x=\dfrac{6}{5}}$

Verification:-

For verification, we have to put value of x in given equation

$\sf{L.H.S.=\dfrac{3(2+\dfrac{6}{5} )-5(2\times\dfrac{6}{5}-3)}{5-3\times\dfrac{6}{5}}}$

Using BODMAS,

$\sf{L.H.S.=\dfrac{3(\dfrac{10+6}{5} )-5(\dfrac{12}{5}-3)}{5-\dfrac{18}{5}}}$

$\sf{L.H.S.=\dfrac{3(\dfrac{16}{5} )-5(\dfrac{12-15}{5})}{\dfrac{25-18}{5}}}$

$\sf{L.H.S.=\dfrac{(\dfrac{48}{5} )-5(\dfrac{-3}{5})}{\dfrac{7}{5}}}$

$\sf{L.H.S.=\dfrac{\dfrac{48}{5}+\dfrac{15}{5}}{\dfrac{7}{5}}}$

$\sf{L.H.S.=\dfrac{\dfrac{48+15}{5}}{\dfrac{7}{5}}}$

$\sf{L.H.S.=\dfrac{\dfrac{63}{5}}{\dfrac{7}{5}}}$

$\sf{L.H.S.=\dfrac{63}{7}}$

$\sf{L.H.S.=9}$

$\sf{L.H.S.=R.H.S.}$

Hence Proved

Answer 2

The final answer is "1.8"

Step-by-step explanation:

$\ Given \ value:\\\\\frac{3(2+x)-5(2x-3)}{5-3x}=9\\\\\ Solution:\\\\\frac{3(2+x)-5(2x-3)}{5-3x}=9\\\\\rightarrow \frac{6+3x-10x+15}{5-3x}=9\\\\\rightarrow \frac{9-7x}{5-3x}=9\\\\\rightarrow (9-7x)=9(5-3x)\\\\\rightarrow 9-7x=45-27x\\\\\rightarrow 27x-7x=45-9\\\\\rightarrow 20x=36\\\\\rightarrow x=\frac{36}{20}\\\\\rightarrow x=\frac{18}{10}\\\\\rightarrow x=1.8$

Learn more:

• Simplify:  https://brainly.in/question/8913062