Math, asked by vashtiwari05181111, 5 months ago

plz find there answer with explanations step by step​

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Answered by BrainlyKingdom
1

Perimeter of Triangle = Sum of All Sides

⇒ Perimeter of Triangle = (3a² - 2a + 5) + (a² + 8) + (4a² - a - 5)

⇒ Perimeter of Triangle = 3a² - 2a + 5 + a² + 8 + 4a² - a - 5

⇒ Perimeter of Triangle = 3a² + a² + 4a² - 2a - a + 5 + 8 - 5

⇒ Perimeter of Triangle = 8a² - 3a + 8

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\put(-1, 1.6){$\bf 3a^2 - 2a + 5$}\qbezier(5,0)(5,0)(3,3)\put(5.0, 1.6){$\bf a^2 + 8 $}\qbezier(5,0)(1,0)(1,0)\put(2.4, - 0.9){$\bf 4a^2 - a - 5 $}\put(2.85,3.2){$\bf A$}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\end{picture}

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Distance Travelled By Bus = Total Distance - Distance Covered by Train

⇒ Distance Travelled By Bus = (7p² - 3p + 4) - (10p² + p²)

⇒ Distance Travelled By Bus = 7p² - 3p + 4 - 10p² - p²

⇒ Distance Travelled By Bus = 7p² - 10p² - p² - 3p + 4

⇒ Distance Travelled By Bus = -4p² - 3p + 4

Answered by Honnushree
1

Answer:

5.

3a ^{2} - 2a + 5 + a ^{2}  + 8 + \\  4a ^{2} - a - 5  = p  \\ 8a ^{2}  - 3a + 8 = p

Step-by-step explanation:

5Q.perimeter =sum of length of all sides of triangle

6Q. let distance travelled by bus be X. thus total distance travelled by bus & train together =distance by train +distance by bus

7p {}^{2} - 3p + 4 = 10p + p {}^{2} + x  \\ 6p {}^{2} - 13 p + 4 = x

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