plz find values of all literal terms in this pic
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ABCD is a ║gm,
∠DAB+∠ABC=180°(sum of adjacent ∠s of a ║gm is 180°)
120°+∠ABC=180°⇒∠ABC=180-120=60°
PQRS is a ║gm,
∠QPS=50°(opp.∠s of a ║gm are equal)
x+60+50=180(sum of ∠s of a Δ is 180°)
x+110=180⇒x=180-110=70°
∠DAB+∠ABC=180°(sum of adjacent ∠s of a ║gm is 180°)
120°+∠ABC=180°⇒∠ABC=180-120=60°
PQRS is a ║gm,
∠QPS=50°(opp.∠s of a ║gm are equal)
x+60+50=180(sum of ∠s of a Δ is 180°)
x+110=180⇒x=180-110=70°
payal73:
pls ans. other questions also it will be very helpful for me
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