Math, asked by tejanshukalyan01, 7 hours ago

plz get me all que answers with explanation on a page ​

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Answers

Answered by dud77457
1

(10) sin30°.tan45° = (1/2).(1)= 1/2

therefore options (c) is correct answer.

(11) If cosA= 4/5 then tanA= 3/4

(12) {tan²60°-sin²30°}/{ tan²45°+cos²30°}

= [(√3)²-(1/2)²]/[(1)²+(√3/2)²

= [3-1/4]/[1+3/4]

= (11/4)/(7/4)

=11/7

option (D).is correct answer.

(13)X=rsin∅ y= rcos∅

then x²+y²= r²(sin²∅+cos²∅)= r²×1=r²

option (b) is right answer.

(14)if 3sec∅-5=0 then sec∅= 5/3 and then

cot∅= 3/4

option(c) is correct answer.

(15)Given

a+b=90° and a= 2b then

3 b=90°

b= 30° then a= 60°

therefore,

cos²a+sin²b= cos²60°+sin²30°

=(1/2)²+(1/2)²

= 1/4+1/4= 2/4= 1/2

therefore option (b) is correct answer.

(16) tanx+sinx= m and tanx-sinx=n then

m²-n²= (tanx+sinx)²-(tanx-sinx)²

=(tanx+sinx+tanx-sinx)(tanx+sinx-tanx+sinx)

= (2tanx)(2sinx)

=4 tanx.sinx=4√mn

option (a) is correct answer.

(17) sec∅+tan∅=x then sec∅-tan∅=1/x

therefore,

sec∅= 1/2(x+1/x)

option (c). is correct answer.

(18) √1+cos∅/1-cos∅= √(1+cos∅)²/1-cos²∅

= √(1+cos∅)²/sin²∅

= (1+cos∅)/sin∅

= cosec∅+cot∅

option (b).is correct answer.

(19) (sin∅/1-cot∅)+(cos∅/1-tan∅)

= [sin²∅/sin∅-cos∅]+[cos²∅/cos∅-sin∅]

= [sin²∅/sin∅-cos∅]-[cos²∅/sin∅-cos∅]

= (sin²∅-cos²∅)/(sin∅-cos∅)

= (sin∅-cos∅)(sin∅+cos∅)/(sin∅-cos∅)

= sin∅+cos∅

option (c) is correct answer.

(20) if sin∅= a/b then tan∅= a/√b²-a²

option (c) is correct answer.

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