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Explanation:
Rate law may be written as
(Rate)1 = k[NO]^x[Cl2]^y
5 X 10^-3 = k[0.380]^x[0.380]^y ------- 1
(Rate)2 = k[NO]^x[Cl2]^y
4 X 10^-2 = k[0.760]^x[0.760]^y-------- 2
(Rate)3 = k[NO]^x[Cl2]^y
1.0 X 10^-2 = k[0.380]^x[0.760]^y -------3
Dividing equation 1 and 2 we get
x+y=1 ----4 (guys I can't type tht so written direct answer hope u understand I will upload the pic of my hand written answer don't worry)
By dividing equation 1 by 3 we get
y = 1
By substitution y =1 in equation 4
x+y = 1
x+1=1
x=1-1
x=0
Rate law can be expressed as ;
Rate = k[NO]^x[Cl2]^y
There fore rate = k[NO]^0[Cl2]^1
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