Question

plz. give answer of this question

Answer 1

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Answer 2

Heya !!

Since, A, B and C are the inner angles of a ∆ABC.

So, A + B + C = 180°

B + C = 180° – A

Dividing by 2 on both sides

(B + C) / 2 = 90° – A/2

Now, tan (B + C) / 2 – L.H.S.

=> tan (90° – A/2)

=> cot A/2 – R.H.S.