plz give answer plzzzz
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1
Answer:
sum of zeroes = -b/a
(a)+(a-b)+(a+b)= 3
3a = 3
a=1
product of zeroes = -d/a
a^3-ad^2= (1)^3-1*d^2
1-d^2= -1
d^2= 2
d= √2
hope it will help you
Answered by
0
Answer:
a = 1 & d = √2
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