Math, asked by vikas7131, 1 year ago

plz give answer plzzzz​

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Answered by ButterFliee
1

Answer:

sum of zeroes = -b/a

(a)+(a-b)+(a+b)= 3

3a = 3

a=1

product of zeroes = -d/a

a^3-ad^2= (1)^3-1*d^2

1-d^2= -1

d^2= 2

d= √2

hope it will help you

Answered by Anonymous
0

Answer:

a = 1 & d = √2

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