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When aluminum reacts with sodium hydroxide solution, the product formed is??
B) NaAIO2 ✅
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1)
2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2.
2)
AI + 3NaOH = AIOH3 ⇓ + 3Na
2Na + 2H2O = 2NaOH + H2 ⇑
AI(OH)3 + NaOH = Na [AL(OH)4]
2AI + 2NaOH + 6H2O =2Na [AICOH] + 3 H2 ⇑
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