plz give detailed solutioun to this numrrical
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Second pendulum = T = 2π×√l/g
then
g= 10ms-^2 and π = 3.14
= 2×3.14×√l/10
=1.40 ms-^2 something
then
g= 10ms-^2 and π = 3.14
= 2×3.14×√l/10
=1.40 ms-^2 something
Answered by
2
Explanation:
1.42m/s²
hope it's helps you to
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