question number 14 only
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⭐⭐Hello friend..Ur answer is here⤵⤵
⚫ p (x)=x^4-2x^3+3x^2-ax+b
➡If divided by x-1 then put the value x=1 in above polynomial
➡(1)^4-2×(1)^3+3 (1)^2-a×1+b=5
➡1-2+3-a+b=5
➡2-a+b=5
➡a-b= -3 ➡ equation 1
Now if divided by x+1 then put the value of x= -1 in above polynomial
➡(- 1)^4-2×(-1)^3+3 (-1)^2-a×(-1)+b=19
➡1+2+3+a+b=19
➡a+b=13➡equation 2
Solving equation 1 and 2 we get
➡a=5 and b=8
⚫Now the remainder when it divided by x-2 means put x=2
➡ (2)^4-2×(2)^3+3 (2)^2-5×2+8
➡16-16+12-10+8
➡10
I HOPE IT IS HELPFUL TO YOU ☺
⚫ p (x)=x^4-2x^3+3x^2-ax+b
➡If divided by x-1 then put the value x=1 in above polynomial
➡(1)^4-2×(1)^3+3 (1)^2-a×1+b=5
➡1-2+3-a+b=5
➡2-a+b=5
➡a-b= -3 ➡ equation 1
Now if divided by x+1 then put the value of x= -1 in above polynomial
➡(- 1)^4-2×(-1)^3+3 (-1)^2-a×(-1)+b=19
➡1+2+3+a+b=19
➡a+b=13➡equation 2
Solving equation 1 and 2 we get
➡a=5 and b=8
⚫Now the remainder when it divided by x-2 means put x=2
➡ (2)^4-2×(2)^3+3 (2)^2-5×2+8
➡16-16+12-10+8
➡10
I HOPE IT IS HELPFUL TO YOU ☺
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