Question

Plz give explanation​

Answer 1

Given,

• Efficiency (η) = 80% = $\sf\dfrac{80}{100}$

• Number of turns in primary ($\sf N_p$) = 300

• Number of turns in secondary ($\sf N_s$) = 1200

• Resistance in primary ($\sf R_p$) = 0.82 Ω

• Resistance in secondary ($\sf R_s$) = 6.2 Ω

• Secondary voltage ($\sf V_s$) = 1600 V  

• Out Power = 32 kW = 32 × 10³ W

We know,

$\huge\boxed{\sf Power_{out} = V_sI_s}$

$\implies\huge\boxed{\sf I_s=\dfrac{Power_{out}}{V_s}}$

$\implies\sf I_s=\dfrac{32\times 10^3}{1600}$

$\implies\sf I_s=20\:A$

Efficiency,

$\huge\boxed{\sf \eta =\dfrac{Power_{out}}{Power_{in}}}$

$\implies\sf \dfrac{80}{100}=\dfrac{32\times 10^3}{Power_{in}}$

$\implies\sf Power_{in}=\dfrac{32\times10^3\times100}{80}$

$\implies\sf Power_{in}=\dfrac{32\times 10^4}{8}$

$\implies\sf Power_{in}=4\times 10^4\:W$

We know,

$\huge\boxed{\sf \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}}$

$\implies\huge\boxed{\sf V_p=\dfrac{V_sN_p}{N_s}}$

Applying the values to the equation,

$\implies\sf V_p=\dfrac{1600\times 300}{1200}$

$\implies\sf V_p=400\:V$

$\huge\boxed{\sf Power_{in}=V_pI_p}$

$\implies\huge\boxed{\sf I_p=\dfrac{Power_{in}}{V_p}}$

$\implies\sf I_p=\dfrac{40000}{400}$

$\implies\sf I_p=100\:A$

$\huge\boxed{\sf Power \:loss \:in \:primary = I^2_p}$

$\implies\sf R_p= (100)^2 \times 0.82$

$\implies\sf R_p= 8200\:W$

$\implies\sf R_p= 8.2\:kW$

$\huge\boxed{\sf Power \:loss \:in \:secondary = I^2_s}$

$\implies\sf R_s= (20)^2 \times 6.2$

$\implies\sf R_s= 2480\:W$

$\implies\sf R_s= 2.48\:kW$

________________________

Therefore,

$\huge\boxed{\sf Power \:loss \:in \:primary = 8.2\:kW}$

$\huge\boxed{\sf Power \:loss \:in \:secondary =2.48\:kW}$

Answer 2

Answer:

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