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Maryamkhan123:
In ∆PQR and ∆PSR , PQ=SR (given), PR= PR(common) angle QPR= angle RPS (alternate) so ∆PQR and ∆PSR are similar by SAS therefore Angle QPR= angle PRS
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When PQ||SR and PR is transversal
<QPR = <PRS (alternate angles)
No, triangle PQR is not congruent to triangle RSP because all elements are not equal According to CPCT(triangle PQR is congruent to triangle RSP)
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