Question

Plz give me the converse of pythagoras theorem

Answer 1

Step-by-step explanation:

GIven a ΔABC, with BC = a, AC = b and AB = c.

Also given, c2 = a2 + b2  --- (1)

Now construct a right angled ΔDEF, with sides EF = BC = a, AC = DF = b.

Let DE = d and ∠EFD = 90°.

SInce, ΔDEF is a right angled triangle, we can use Pythagoras theorem,  

⇒ d2 = a2 + b2

But by (1),  c2 = a2 + b2  

Therefore, c = d

i.e. AB = DE  

Thus, by construction , By SSS test, ΔABC ≃ ΔDEF  

Thus, ΔABC is a right angled triangle with ∠ACB = 90°.

Answer 2

Answer:

Step-by-step explanation

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