Math, asked by Harpalkamboj66, 9 months ago

Plz give me the correct answer only ..it is very urgent plz help me ans. Quickly Let * be the binary operation on R be the real numbers defined as a*b = a+b,then the value of 6*(3*3) is -------

Answers

Answered by tonidyana
0

Answer:

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Step-by-step explanation:

ANSWER

(i)  a∗b=a−b

Check commutative is

a∗b=b∗a

a∗b=a−b

b∗a=b−a

Since, a∗b  

​  

=b∗a

∗ is not commutative.

Check associative

∗ is associative if

(a∗b)∗c=a∗(b∗c)

(a∗b)∗c=(a−b)  

c=(a−b)−c=a−b−c

a∗(b∗c)=a∗(b−c)=a−(b−c)=a−b+c

Since (a∗b)∗c  

​  

=a∗(b∗c)

∗ is not an associative binary operation.

(ii)  a∗b=a  

2

+b  

2

 

Check commutative

∗ is commutative if a∗b=b∗a

a∗b=a  

2

+b  

2

 

b∗a=b  

2

+a  

2

=a  

2

+b  

2

 

Since a∗b=b∗a∀a,bϵQ

∗ is commutative.

Check associative

∗ is associative if

(a∗b)∗c=a∗(b∗c)

(a∗b)∗c=(a  

2

+b  

2

)∗c=(a  

2

+b  

2

)  

2

+c  

2

 

a∗(b∗c)=a∗(b  

2

+c  

2

)=a  

2

+(b  

2

+c  

2

)  

2

 

Since (a∗b)∗c  

​  

=a∗(b∗c)

∗ is not an associative binary operation.

(iii) a∗b=a+b

Check commutative

∗ is commutative is a∗b=b∗a

a∗b=a+ab;b∗a=b+ba

Since a∗b  

​  

=b∗a

∗ is not commutative.

(iv) a∗b=(a−b)  

2

 

Check commutative

∗ is commutative if a∗b=b∗a

a∗b=(a−b)  

2

;b∗a=(b−a)  

2

=(a−b)  

2

 

Since a∗b=b∗a∀a,bϵQ

∗ is commutative.

Check associative

∗ if

(a∗b)∗c=a∗(b∗c)

(a∗b)∗c=(a−b)  

2

∗c=[(a−b)  

2

−c]  

2

 

a∗(b∗c)=a∗(b−c)  

2

=[a−(b−c)  

2

]  

2

 

Since (a∗b)∗c  

​  

=a∗(b∗c)

∗ is not an associative binary operation.

(v) a∗b=  

4

ab

​  

 

Check commutative.

∗ is commutative if a∗b=b∗a

a∗b=  

4

ab

​  

;b∗a=  

4

ba

​  

=  

4

ab

​  

 

Since a∗b=b∗a∀a,bϵQ

∗ is commutative.

Check associative.

∗ is association if (a∗b)∗c=a∗(b∗c)

(a∗b)∗c=(  

4

4

ab

​  

∗c

​  

)=  

16

abc

​  

 

a∗(b∗c)=a∗(  

4

bc

​  

)=  

4

a×  

4

bc

​  

 

​  

=  

16

abc

​  

 

Since (a∗b)∗c=a∗(b∗c)∀a,b,cϵQ

∗ is an associative binary operation.

(vi) a∗b=ab  

2

 

check commutative.

∗ is commutative if a∗b=b∗a

a∗b=ab  

2

;b∗a=ba  

2

 

Since a∗b  

​  

=b∗a

∗ is not commutative.

Check associative  

∗ is associative if (a∗b)∗c=a∗(b∗c)

(a∗b)∗c=ab  

2

∗c=(ab  

2

)c  

2

=ab  

2

c  

2

.

a∗(b∗c)=a∗bc  

2

=a(bc  

2

)  

2

=ab  

2

c  

4

 

Since (a∗b)∗c  

​  

=a∗(b∗c)

∗ is not an associate binary operation.

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