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Dimensions = a , b and c.
=> Volume of cuboid = l × b × h
=> V = abc ------------ ( 1 )
And ,
=> Surface area of cuboid = 2 ( lb + bh + lh )
=> S = 2 ( ab + bc + ac ) --------- ( 2 )
By dividing ( 2 ) by ( 1 ) ,
=> S/V = 2 ( ab + bc + ac ) ÷ abc
=> S/V = ( 2ab + 2bc + 2ac ) ÷ abc
=> S/V = ( 2ab ÷ abc ) + ( 2bc ÷ abc ) + ( 2ac ÷ abc )
=> S/V = ( 2/c ) + ( 2/a ) + ( 2/b )
Taking out 2 as common in R.H.S,
=> S/V = 2 { ( 1/c ) + ( 1/a ) + ( 1/b ) }
Rearranging the terms ,
=> S/V = 2 { ( 1/a ) + ( 1/b ) + ( 1/c ) }
=> 1/V = ( 2/S ) { ( 1/a ) + ( 1/b ) + ( 1/c ) }
hence it is proved
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