Math, asked by Anonymous, 10 months ago

plz give the answer of this question. ​

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Answered by arvishaali2004
1

Answer:

Step-by-step explanation:

Let x be any positive integer

Then x = 5q or x = 5q+1 or x = 5q+4  for integer x.

If x = 5q, x2 = (5q)2 = 25q2 = 5(5q2) = 5n (where n = 5q2 )

If x = 5q+1, x2 = (5q+1)2 = 25q2+10q+1 = 5(5q2+2q)+1 = 5n+1 (where n = 5q2+2q )

If x = 5q+4, x2 = (5q+4)2 = 25q2+40q+16 = 5(5q2 + 8q + 3)+ 1 = 5n+1 (where n = 5q2+8q+3 )

∴in each of three cases x2 is either of the form 5q or 5q+1 or 5q+4 and for integer q.

Pls mark my answer as "Brainliest"!!!!!!!

Hope it helps:)


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Answered by Anonymous
1

First of all thanks for this question :D

Solution to you answer :

Let 'x' be any positive integer

Then x = 5q

x = 5q+1

x = 5q+4  for some integer x.

If x = 5q,

x²= (5q)² = 25q²

= 5(5q²) = 5n (where n = 5q² )

If x = 5q+1,

x² = (5q+1)² = 25q²+10q+1

= 5(5q²+2q)+1 = 5n+1 (where n = 5q²+2q )

If x = 5q+4,

x²= (5q+4)² = 25q²+40q+16

= 5(5q² + 8q + 3)+ 1 = 5n+1 (where n = 5q²+8q+3 )

∴In each of three cases; x² is either of the form 5q or 5q+1 or 5q+4 and for integer q.

Hence your question and answer is proved....

Hope it helps you dear....be brainly. :)

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