plz guys help me ans this questions
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hope it helps comment if any doubt
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AnabBrest:
can it come as u did last step .....is it correct
yes it is a property of similiar triangles
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To prove AP/PD=PC/PD,
We need to prove that triangle PBD≈Triangle APD
Which you can prove by the properties of square
We need to prove that triangle PBD≈Triangle APD
Which you can prove by the properties of square
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