Question

plz guys help me plz ​

Answer 1

Answer:

in triangle ADC,

angle ADC = 180-(70+40) (since, sum of three angles of a triangle=180 degree.so, one of the angle = 180 degree -(sum of other two angles).

so, angle ADC =180°-110

Imply, angle ADC = 70°

now, in triangle DBC,

since,DB=BC

so, triangle DBC is an isosceles triangle

and angle DBC=80°

we know that,

angle of the similar sides of a isosceles triangle is equal

so, angle BDC and angle BCD = (180°-80°)/2.

imply, angle BCD and angle BDC= 100°/2

imply, angle BCD and angle BDC= 50° (each)

Answer 2

i have already answered this

thank you for choosing my answer as brainliest