Math, asked by SwayamSudha05, 1 year ago

plz guys... solve this
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plzzzzzzz​

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Answers

Answered by Anonymous
1

Step-by-step explanation:

AEB is a right angled triangle.

Therefore, by Pythagoras theorem,

AB 2= AE2 + BE2 --------------- (1)

Now, AED is a right angled triangle.

Therefore,

=> AE2 + ED2= AD2 (Pythagoras theorem)

=> AE2 = AD2 - ED2 -------------- (2)

Now, BE = BD - ED ---------------- (3)

Substituting (2) and (3) in (1), we get,

AB2= AD2 - ED2 + (BD - ED)2

=AD2 – ED2 + BD2 -2BD*ED + ED2

= AD2 – ED2 + BD2 -2BD*ED + ED2

Now, BD = BC/2 (since, D is midpoint)

Therefore,

AB2= AD2 + BD2 -2BD*ED

=AD2 + (BC/2)2 – 2(BC/2)*ED

= AD2 + (BC/2)2 – 2(BC/2)*ED

= AD2 – BC*DE + ¼ BC2

Hopea this helps you dude.....

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Answered by sohrat
4

Answer:

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