Question

plz help......
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Answer 1

option A

given

@ = 60°

We know that

moment of inertia of sphere = (2mr^2)/5

and

Torque = Force *perpendicular distance from the line of action of force= IA

so

F*T = IA

F = IA/R= 2MRA/5= 2MA/5

Now using kinetics energy Theorem

(2mgsin@ - f)l =(( 2M)v^2)/2+ (I( omega)^2)/2

(2mgsin@ - f)l = 6mv^2/5

we know that V = R*Omega (conversion from linear to angula velocity)

So

on differentiating above equation we get

(2mgsin@ - f)V = 12Mvdv/dt = 24Mva/5

Now

on putting

f = 2Ma/5

we get

a= 5gsin60/14

a = 5sqrt3g/14