Question

plz help ??????? ___​

Answer 1

$\mathtt{\huge{\underline{\red{Question\:?}}}}$

★ The curved surface area of a right circular cylinder of height 14 cm is 88 cm² . Find the diameter of the base of the cylinder .

$\mathtt{\huge{\underline{\green{Answer:-}}}}$

➡ The Diameter of base of cylinder is 2 cm.

$\mathtt{\huge{\underline{\orange{Explaination :-}}}}$

GᏆᐯᗴᑎ :-

The curved surface area of a right circular cylinder is 88 cm ²

Its height is 14 cm.

Tᝪ ᖴᏆᑎᗞ :-

The diameter of the the cylinderical base.

SᝪᏞᑌᎢᏆᝪᑎ :-

According to the question,

CSA = 2 π r h

The curved surface area of a right circular cylinder is 88 cm ².

➝88 = 2 π r h

We , know that diameter is 2r.

➝$\dfrac{2 \times 22 \times 14 \times r}{7} = 88$

➝ $\dfrac{616 \times r}{7} = 88$

➝ $r = \dfrac{88 \times 7}{616}$

➝ $r = \cancel{\dfrac{616}{616}}$

➝ r = 1 cm

Hence , its founded our radius to be 1 cm.

We know that diameter is 2r

➝ 2 × r

➝ 2× 1

➝ 2 cm

⟹ Hence, The Diameter of base of cylinder is 2cm.

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Answer 2

Refet the attachment..............