Question

plz help........




A mass of 2.9kg suspended from a string of length 50cm is at rest . Another body of 100g moving horizontally with velocity 150m/s strikes and sticks to it. what is tension in the string when it makes the angle of 60degree with the horizontal????? ​

Answer 1

ANSWER

Since the collision is perfectly inelastic, conserving momentum, we get,

0.1×150=(2.9+0.1)×u

u=5 m/s

After this, applying conservation of energy,

(m+M) g(l(1−cos(60))+ ½ (m+M)v²

= ½ (m+M)u²

½ (m+M)v² = ½(m+M)u² −(m+M)gl(1−cos(60)

(m+M)v² =3×5²−2×3×10×0.5×(1−0.5)

⟹(m+M)v² =60

T =(m+M)gcos(θ)+(m+M)v² /l

=15+120

T=135 N

i hope it helps you.