Question

plz help answer the Question​

Answer 1

Answer:

Starting velocity u = 0 m/s

End velocity v= 28m/s in time t= 4sec

If accleration = f

$v= u+at ,$

$28= 0+ a \times 4 \\ a = \frac{28}{4} = 7 m/s^2$

$Accleration = 7m/sec^2$

(b) If distance travelled = S

$S= ut + \frac{1}{2} at^2$

$= 0 \times 4+( \frac{1}{2} ) \times 7 \times 4^2$

$=56 m$

Distance travelled in 4 sec = 56 m

Answer 2

Explanation:

average acceleration =28/4

= 7 m/s²

distance travelled =

$ut + \frac{1}{2} a {t}^{2}$

but u=0

therefore s =1/2 at²

s=1/2×7×4×4

s=56 m