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Step-by-step explanation:
so the above equation could be written as
(2^x)^2-8(2^x)=-16
taking 2^x as common
2^x[2^x-8]=-2^2×2^2
Comparing
2^x=2^2 and 2^x-8=-2^2
X=2 and 2^x=-4+8
X=2 and 2^x=4
X=2 and X= 2
so from both u get X=2
Pls mark me as brainiest
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