Math, asked by nemo29, 1 year ago

plz help fast fast......

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Answered by Anonymous
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= sin( 90 - θ) cos (90 - θ)

= sinθ × cosθ

multipying and dividing with 2

⇒ 2/2(sinθ × cosθ)

⇒ 1/2(2 sinθ × cosθ)

⇒ 1/2(sin2θ)

⇒ 1/2(2tanθ/(1 + tan²θ))

⇒ tanθ/(1 + tan²θ)

  • sin2θ = 2tanθ/1 + tan²θ


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