Question

PLZ HELP!!! GEOMETRY ASAP

Answer 1

Answer:

First join AO and BQ.

( I am sorry I am not able to put a picture but you will surely understand continue reading )

We know that, tangents are perpendicular to the radii of the circle.

Hence AO and BQ are perpendicular to AC.

Now in triangles AOC and BQC,

angle OAC = angle BQC = 90 DEGREES.

and

angle ACO = angle BCQ

By AA similarity, triangles ACO and BCQ are similar.

So according to the properties of similar triangles,

AO / QB = CO / CQ.

Hence proved.

Please mark me as the Brainliest.

I did my level best to make it easily understandable.

please ignore if any grammatical mistakes are present.