plz help guys ... and answer shoup be shown properly
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x=1
y=2
z=3
x+y+z=6
=1+2+3
=6
=14
xy+yz+xz
1×2+2×3+1×3
2+6+3=11
y=2
z=3
x+y+z=6
=1+2+3
=6
=14
xy+yz+xz
1×2+2×3+1×3
2+6+3=11
adityakumar96:
this answer is to be done using identity
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