Question

❤️..plz help..if x=√3+√2/√3-√2..find xsquare+1/xsquqre.....who will answer me i will thank his/her answers​

Answer 1

√3+√2 √3+√2

x= --------------- x -----------

√3-√2 √3+√2

(√3+√2)(√3+√2)

x= -----------------------------

(√3-√2)(√3+√2)

x = (√3×√3) + (√2×√2) + 2√3×√2

-------------------------------------------------

(√3×√3)(√2×√2)

3 + 2 + 2√6

x = -------------------

3 - 2

2 (3+√6)

x = -----------------

1

x = 3+√6

Therefore = x²+1/x² According to Question

According to Question Put Value of x in Given...So it Will be like this :

x²+1

x= ----------

x²

(3+√6 × 3+√6) + 1

x= -------------------------------

(3+√6 × 3+√6)

(3 × 3) + (√6 × √6) + 2×3×√6 +1

x= ----------------------------------------------------

(3 × 3) + (√6 × √6) + 2×3×√6

9 + 6 + 6√6 + 1

x= -------------------------

9 + 6 + 6√6

15+ 1 + 6√6

x= ---------------------

15 + 6√6

16 + 6√6

x= ---------------

16 + 6√6

x = 1

I Hope This is Helpful for you......

Answer 2

Answer:

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