Question

plz help in solving this

Answer 1

here's the answer. hope you understand

Answer 2

L.H.S

(1+tan²@) + (1+1/tan²@),


sec²@ + (tan²@+1)/tan²@,


sec²@ + sec²@/tan²@,


sec²@[1+1/tan²@],



sec²@[tan²@+1]/tan²@,


sec²@.sec²@/tan²@,


1/cos²@ . 1/cos²@ . cos²@/sin²@,


1/sin²@.cos²@,


now taking R.H.S, we have


1/[sin²@(1-sin²@)],


1/[sin²@.cos²@],


hence

L.H.S = R.H.S