Water in acanal,5.4 m wide and 1.8 m deep is flowing with aspeed of 25km/hr .how much it can irrigate in 40 min if 10 cm of standing water is required for irrigation
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b= 5.4 m
h=1.8m
v= 25 km/h
therefore, l=25km per hour
therefore water that would be flowing in40minutes
=40*25/60=50/3km=50000/3m
area of irrigation= area water flowing in 40minutes
volume of water which irrigates the land= volume water flowing from canal in 40 minutes and 10 cm or 1/10 m of standing water is required for irrigation
therefore,
l*b*h=L*B*H
l*b*1/10=50000/3*5.4*1.8
l*b=300000*5.4
l*b=16200000sq. m
therefore, area to be irrigated when 10 cm of standing water is required=16200000sq. m
h=1.8m
v= 25 km/h
therefore, l=25km per hour
therefore water that would be flowing in40minutes
=40*25/60=50/3km=50000/3m
area of irrigation= area water flowing in 40minutes
volume of water which irrigates the land= volume water flowing from canal in 40 minutes and 10 cm or 1/10 m of standing water is required for irrigation
therefore,
l*b*h=L*B*H
l*b*1/10=50000/3*5.4*1.8
l*b=300000*5.4
l*b=16200000sq. m
therefore, area to be irrigated when 10 cm of standing water is required=16200000sq. m
anuritha:
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