Question

plz help in the question​

Answer 1

I hope this helps you!!

Answer 2

Given :-

• AD = AE
• ∠ BAD = ∠ CAE

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To prove :-

• AB = AC

Proof :-

→  ∵ AD = AE

→  ∴  ∠ AED = ∠ ADE

(angles opposite to equal sides)

→  180 - ∠ AED = 180 - ∠ ADE

Now, since

∠ ADE and ∠ ADB form linear pair and

∠ AED and ∠ AEC form linear pair therefore,

→ ∠ AEC = ∠ ADB  ....eqn(1)

Now,

consider Δ ABD and Δ ACE

AD = AE  (given)

∠ BAD = ∠ CAE (given)

∠ AEC = ∠ ADB  (by eqn (1) )

so, using ASA congruency criterian

Δ ABD = Δ ACE

therefore,

→  AB = AC

(being corresponding parts of congruent triangles)

Proved .