Math, asked by hiranjetpatnaikpatna, 4 months ago

Ten years later a will be. as old as b and five years ago a was three times as old as b what are the present age of a and b. explain with step by step. ​

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Answered by linap33
1

Step-by-step explanation:

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Answered by SakshamKumarthegreat
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Call A and B the 2 present ages.

Ten years from now, A is twice as old as B

(A + 10) = 2(B + 10)................ (1)

Five years ago, A was 3 times as old as B

(A - 5) = 3(B - 5) .....................(2).

Solve the system (1) and (2).

From (2) --> A = 3B - 15 + 5 = 3B - 10.

Replace this value of A into (1) -->

3B - 10 + 10 = 2B + 20

B = 20

Present age of B is20.

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