Ten years later a will be. as old as b and five years ago a was three times as old as b what are the present age of a and b. explain with step by step.
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Call A and B the 2 present ages.
Ten years from now, A is twice as old as B
(A + 10) = 2(B + 10)................ (1)
Five years ago, A was 3 times as old as B
(A - 5) = 3(B - 5) .....................(2).
Solve the system (1) and (2).
From (2) --> A = 3B - 15 + 5 = 3B - 10.
Replace this value of A into (1) -->
3B - 10 + 10 = 2B + 20
B = 20
Present age of B is20.
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