Question

*PLZ HELP IT'S DUE IN 2HRS*
A car is moving at 7 m/s when it accelerates at a rate of -2 m/s until it comes to a stop. What is the time it takes to come to rest? List the givens *

Answer 1

Physics

First Velocity (Vo) = 7 m/s

acceleration (a) = -2 m/s²

Last Velocity (Vt) = 0 (because it stops)

Time : ____?

Answer :

Vt = Vo + a × t

0 = 7 + (-2) × t

-7 = (-2)t

3,5 seconds = t

Answer 2

Given :

• Initial velocity (u) = 7 m/s
• Final velocity (v) = 0 m/s
• Acceleration (a) = -2 m/s²

To find :

• Time (t)

According to the question,

→ v = u + at

Where,

• v stands for Final velocity
• u stands for Initial velocity
• t stands for Time
• a stands for Acceleration

→ Substituting the values,

→ 0 = 7 + (-2) × t

→ 0 - 7 = -2t

→ -7 = -2t

→ 7 ÷ 2 = t

→ 3.5 = t

So,the time is 3.5 seconds...

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More formula's :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as