Question

*PLZ HELP IT'S DUE IN 2HRS*
A sprinter runs in a race. She starts from rest and runs for 12 seconds with an acceleration of 2.2 m/s2. What is the magnitude of her displacement? (Kinematic equations)

Answer 1

Explanation:

u =0. , t= 12 , a= 2.2

v= u+ at

v= 0+2.2×12

v=26.4

displacement = v/t

=26.4/12

=2.2 m

Answer 2

Physics

First Velocity (Vo) = 0 (because it's from the start)

Time (t) = 12 seconds

Acceleration = 2,2 m/s²

Displacement (d) = ____?

Last Velocity (Vt) = ___?

Answer :

Vt = Vo + a × t

Vt = 0 + 2,2 × 12

Vt = 26,4 m/s

d = v × t + 1/2 × a × t

D = 26,4 × 12 + 1/2 × 2,2 × 12²

D = 316,8 + 1/2 × 2,2 × 144

D = 316,8 + 1/2 × 316,8

D = 316,8 + 158,4

D = 475,2 meters