plz help me......... a uniform rod 60 meters long is pivoted at its midpoint and used a seesaw jean who weighs 50 n sits 10 meters from the left end john sit 2 meter from right end what is weight of john seesaw is to balance?
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This is a question on equilibrium.
For a system in equilibrium clockwise moments equals to anticlockwise moments.
The formula for getting moments is as given below:
Moments = Force × distance
Since the pivot is placed at the midpoint each side of the seesaw is of length 30m
The moments on the left are anticlockwise whereas the moments on the right are clockwise moments.
Clockwise moments.
Let the weight be x
the distance from the pivot is :
30 -2 = 28 m
Moments = 28x
Anticlockwise moments
Force = 50N
Distance = 30 - 10 = 20 m
Moments = 20 × 50 = 1000
For the system to be in equilibrium the clockwise moments should be equal to the anticlockwise moments.
We therefore equate the two as follows :
28x = 1000
x = 1000/28 = 35.71 N
35.71 N
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Answer:
100N answer hay please give explanation
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