Math, asked by Tharani6, 1 year ago

plz help me and send fast

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Answers

Answered by kartiksuri2411
6
X-Y=5
XY=24
X+Y=?
(X-Y)^2=X^2+Y^2+2XY
(5)^2=X^2+Y^2+2(24)
25=X^2+Y^2+48
X^2+Y^2=25-48
X^2+Y^2=-23
REST OF THE SUM IS ATTACHED IN PHOTO...
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Answered by Anonymous
10
Hey friend

Here is your answer

GIVEN :
_____

x>y

THEIR DIFFERENCE =5

x-y=5

x=y+5

THEIR PRODUCT =24

ACCORDING TO QUESTION :

x×y=24

(y+5)y=24

y²+5y-24=0

y²+8y-3y-24=0

y(y+8)-3(y+8)=0

(y+8)(y-3)=0

y= -8 (rejected as the numbers are positive)

or y=3

WHEN y=3
_________
x=y+5

x=3+5

x=8
===============================

WE GET
x=8
y=3

===============================

1)SUM OF THESE NUMBERS :

=x+y

=8+3

=11

===============================

2)DIFFERENCE OF THEIR CUBES :

=x³-y³

=(8)³-(3)³

=512-27

=485

===============================

3)SUM OF THEIR CUBES :

=x³+y³

=(8)³+(3)³

=512+27

=539

===============================

HOPE THIS HELPS YOU ☺

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