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X-Y=5
XY=24
X+Y=?
(X-Y)^2=X^2+Y^2+2XY
(5)^2=X^2+Y^2+2(24)
25=X^2+Y^2+48
X^2+Y^2=25-48
X^2+Y^2=-23
REST OF THE SUM IS ATTACHED IN PHOTO...
MARK AS BRAINLIEST
XY=24
X+Y=?
(X-Y)^2=X^2+Y^2+2XY
(5)^2=X^2+Y^2+2(24)
25=X^2+Y^2+48
X^2+Y^2=25-48
X^2+Y^2=-23
REST OF THE SUM IS ATTACHED IN PHOTO...
MARK AS BRAINLIEST
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Hey friend
Here is your answer
GIVEN :
_____
x>y
THEIR DIFFERENCE =5
x-y=5
x=y+5
THEIR PRODUCT =24
ACCORDING TO QUESTION :
x×y=24
(y+5)y=24
y²+5y-24=0
y²+8y-3y-24=0
y(y+8)-3(y+8)=0
(y+8)(y-3)=0
y= -8 (rejected as the numbers are positive)
or y=3
WHEN y=3
_________
x=y+5
x=3+5
x=8
===============================
WE GET
x=8
y=3
===============================
1)SUM OF THESE NUMBERS :
=x+y
=8+3
=11
===============================
2)DIFFERENCE OF THEIR CUBES :
=x³-y³
=(8)³-(3)³
=512-27
=485
===============================
3)SUM OF THEIR CUBES :
=x³+y³
=(8)³+(3)³
=512+27
=539
===============================
HOPE THIS HELPS YOU ☺
Here is your answer
GIVEN :
_____
x>y
THEIR DIFFERENCE =5
x-y=5
x=y+5
THEIR PRODUCT =24
ACCORDING TO QUESTION :
x×y=24
(y+5)y=24
y²+5y-24=0
y²+8y-3y-24=0
y(y+8)-3(y+8)=0
(y+8)(y-3)=0
y= -8 (rejected as the numbers are positive)
or y=3
WHEN y=3
_________
x=y+5
x=3+5
x=8
===============================
WE GET
x=8
y=3
===============================
1)SUM OF THESE NUMBERS :
=x+y
=8+3
=11
===============================
2)DIFFERENCE OF THEIR CUBES :
=x³-y³
=(8)³-(3)³
=512-27
=485
===============================
3)SUM OF THEIR CUBES :
=x³+y³
=(8)³+(3)³
=512+27
=539
===============================
HOPE THIS HELPS YOU ☺
Anonymous:
perfect..!
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